时间:2021-03-03 10:08:45 | 栏目:Mysql | 点击:次
在为一个客户排除死锁问题时我遇到了一个有趣的包括InnoDB间隙锁的情形。对于一个WHERE子句不匹配任何行的非插入的写操作中,我预期事务应该不会有锁,但我错了。让我们看一下这张表及示例UPDATE。
mysql> SHOW CREATE TABLE preferences \G *************************** 1. row *************************** Table: preferences Create Table: CREATE TABLE `preferences` ( `numericId` int(10) unsigned NOT NULL, `receiveNotifications` tinyint(1) DEFAULT NULL, PRIMARY KEY (`numericId`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 1 row in set (0.00 sec) mysql> BEGIN; Query OK, 0 rows affected (0.00 sec) mysql> SELECT COUNT(*) FROM preferences; +----------+ | COUNT(*) | +----------+ | 0 | +----------+ 1 row in set (0.01 sec) mysql> UPDATE preferences SET receiveNotifications='1' WHERE numericId = '2'; Query OK, 0 rows affected (0.01 sec) Rows matched: 0 Changed: 0 Warnings: 0
---TRANSACTION 4A18101, ACTIVE 12 sec 2 lock struct(s), heap size 376, 1 row lock(s) MySQL thread id 3, OS thread handle 0x7ff2200cd700, query id 35 localhost msandbox Trx read view will not see trx with id >= 4A18102, sees < 4A18102 TABLE LOCK table `test`.`preferences` trx id 4A18101 lock mode IX RECORD LOCKS space id 31766 page no 3 n bits 72 index `PRIMARY` of table `test`.`preferences` trx id 4A18101 lock_mode X
这是为什么呢,Heikki在其bug报告中做了解释,这很有意义,我知道修复起来很困难,但略带厌恶地我又希望它能被差异化处理。为完成这篇文章,让我证明下上面说到的死锁情况,下面中mysql1是第一个会话,mysql2是另一个,查询的顺序如下:
mysql1> BEGIN; Query OK, 0 rows affected (0.00 sec) mysql1> UPDATE preferences SET receiveNotifications='1' WHERE numericId = '1'; Query OK, 0 rows affected (0.00 sec) Rows matched: 0 Changed: 0 Warnings: 0 mysql2> BEGIN; Query OK, 0 rows affected (0.00 sec) mysql2> UPDATE preferences SET receiveNotifications='1' WHERE numericId = '2'; Query OK, 0 rows affected (0.00 sec) Rows matched: 0 Changed: 0 Warnings: 0 mysql1> INSERT INTO preferences (numericId, receiveNotifications) VALUES ('1', '1'); -- This one goes into LOCK WAIT mysql2> INSERT INTO preferences (numericId, receiveNotifications) VALUES ('2', '1'); ERROR 1213 (40001): Deadlock found when trying to get lock; try restarting transaction
现在你看到导致死锁是多么的容易,因此一定要避免这种情况――如果来自于事务的INSERT部分导致非插入的写操作可能不匹配任何行的话,不要这样做,使用REPLACE INTO或使用READ-COMMITTED事务隔离。