c++回调之利用函数指针示例

#include <iostream>
using namespace std;

/************************************************************************/
/*                下层实现: CALLBACK                                        */
/************************************************************************/

typedef void (*CALLBACKFUN)(int a,int b);

class base
{
private:
    int m;
    int n;
    static CALLBACKFUN pfunc;
public:
    base():m(0), n(0){};
    void registercallback(CALLBACKFUN fun,int k,int j);
    void callcallback();
};

CALLBACKFUN base::pfunc=NULL;    /* static初始化 */

// 注册回调函数
void base::registercallback(CALLBACKFUN fun,int k,int j)
{
    pfunc=fun;
    m=k;
    n=j;
}

void base::callcallback()
{
    base::pfunc(m,n);
}

// cbByfunction.cpp : Defines the entry point for the console application.
//

#include "stdafx.h"
#include "cbByfunction.h"

/************************************************************************/
/*                    上层回调注册                                        */
/************************************************************************/
void seiya(int a,int b)
{
    cout << "..." << a << "..." << b << endl;
    cout << "this is seiya callback function" <<endl;
}

void zilong(int a,int b)
{
    cout<<a<<endl<<b<<endl;
    cout<<"this is zilong callback function"<<endl;
}

int main(int argc, char* argv[])
{
    // 注册下层回调函数
    base c_base;
    c_base.registercallback(seiya, 5, 6);
    c_base.callcallback();
    c_base.registercallback(zilong, 7, 8);
    c_base.callcallback();
    return 0;
}