时间：2023-01-26 09:45:27 | 栏目：Python代码 | 点击：次
>>> "{:,}".format(56381779049)
'56,381,779,049'
>>> "{:,}".format(56381779049.1)
'56,381,779,049.1'
>>>
>>> import re >>> subject = '1234567' >>> result = re.sub(r"(?<=\d)(?=(?:\d\d\d)+$)", ",", subject) >>> result '1,234,567'
>>> import re >>> subject = '1234567' >>> result = re.sub(r"(\d)(?=(\d\d\d)+(?!\d))", r"\1,", subject) >>> result '1,234,567'
Python 2.7 (r27:82500, Nov 23 2010, 18:07:12) [GCC 4.1.2 20070115 (prerelease) (SUSE Linux)] on linux2 Type "help", "copyright", "credits" or "license" for more information. >>> format(1234567890,',') '1,234,567,890' >>>
import re
def strConv(s):
s = str(s)
while True:
(s,count) = re.subn(r"(\d)(\d{3})((:?,\d\d\d)*)$",r"\1,\2\3",s)
if count == 0 : break
return s
print strConv(12345)