时间:2023-01-16 12:00:10 | 栏目:Mysql | 点击:次
最近遇到一个业务需求, 需要查找满足条件且连续3出现条以上的记录。
表结构:
CREATE TABLE `cdb_labels` ( `id` int(10) unsigned NOT NULL AUTO_INCREMENT, `type` int(11) NOT NULL DEFAULT '0' COMMENT '标签类型:1喜欢异性类型,2擅长话题', `content` varchar(255) CHARACTER SET utf8 COLLATE utf8_unicode_ci NOT NULL COMMENT '标签内容', PRIMARY KEY (`id`) ) ENGINE=InnoDB AUTO_INCREMENT=57 DEFAULT CHARSET=utf8 COMMENT='标签内容';
所有数据:
SELECT * FROM cdb_labels WHERE type = 1;
select id,type,content,(@b:=@b+1) as b from cdb_labels a,(SELECT @b := 0) tmp_b where type=1;
select id,type,content,( id-(@b:=@b+1) ) as c from cdb_labels a,(SELECT @b := 0) tmp_b where type=1;
select count(id),GROUP_CONCAT(id) from ( select id,( id-(@b:=@b+1) ) as c from cdb_labels a,(SELECT @b := 0) tmp_b where type=1 ) as d GROUP BY c;
注:为了方便区分,这里查询分组成员要大于5(也就是连续出现超过5次的记录):
select if( count(id)>5 ,GROUP_CONCAT(id),null) e from ( select id,( id-(@b:=@b+1) ) as c from cdb_labels a,(SELECT @b := 0) tmp_b where type=1 ) as d GROUP BY c;
那么得到的数据只有:9,10,11,12,13,14,15
select id,type,content from cdb_labels,( select if( count(id)>5 ,GROUP_CONCAT(id),null) e from ( select id,( id-(@b:=@b+1) ) as c from cdb_labels a,(SELECT @b := 0) tmp_b where type=1 ) as d GROUP BY c ) as f where f.e is not null and FIND_IN_SET(id , f.e);