时间：2022-04-24 10:16:50 | 栏目：Mysql | 点击：次
根据圆周率和地球半径系数以及搜寻点的经纬度，搜寻数据表中与搜寻点之间的距离为N公里内的数据。
1、创建测试表
CREATE TABLE `location` ( `id` int(10) unsigned NOT NULL AUTO_INCREMENT, `name` varchar(50) NOT NULL, `longitude` decimal(13,10) NOT NULL, `latitude` decimal(13,10) NOT NULL, PRIMARY KEY (`id`), KEY `long_lat_index` (`longitude`,`latitude`) ) ENGINE=InnoDB DEFAULT CHARSET=utf8;
2、插入测试数据
insert into location(name,longitude,latitude) values
('广州东站',113.332264,23.156206),
('林和西',113.330611,23.147234),
('天平架',113.328095,23.165376);
mysql> select * from `location`;
+----+--------------+----------------+---------------+
| id | name | longitude | latitude |
+----+--------------+----------------+---------------+
| 1 | 广州东站 | 113.3322640000 | 23.1562060000 |
| 2 | 林和西 | 113.3306110000 | 23.1472340000 |
| 3 | 天平架 | 113.3280950000 | 23.1653760000 |
+----+--------------+----------------+---------------+
3、搜寻1公里内的数据
搜寻点坐标：时代广场 113.323568, 23.146436
6370.996公里为地球的半径
计算球面两点坐标距离公式
C = sin(MLatA)sin(MLatB)cos(MLonA-MLonB) + cos(MLatA)cos(MLatB) Distance = RArccos(C)*Pi180
根据计算公式得到查询语句如下：
select * from `location` where ( acos( sin(([#latitude#]*3.1415)/180) * sin((latitude*3.1415)/180) + cos(([#latitude#]*3.1415)/180) * cos((latitude*3.1415)/180) * cos(([#longitude#]*3.1415)/180 - (longitude*3.1415)/180) )*6370.996 )<=1;
执行查询：
mysql> select * from `location` where ( -> acos( -> sin((23.146436*3.1415)/180) * sin((latitude*3.1415)/180) + -> cos((23.146436*3.1415)/180) * cos((latitude*3.1415)/180) * cos((113.323568*3.1415)/180 - (longitude*3.1415)/180) -> )*6370.996 -> )<=1; +----+-----------+----------------+---------------+ | id | name | longitude | latitude | +----+-----------+----------------+---------------+ | 2 | 林和西 | 113.3306110000 | 23.1472340000 | +----+-----------+----------------+---------------+