时间：2022-03-01 10:18:21 | 栏目：Python代码 | 点击：次
1、可以使用send_from_directory从目录发送文件，这在某些情况下非常方便。
from flask import Flask, request, send_from_directory
# set the project root directory as the static folder, you can set others.
app = Flask(__name__, static_url_path='')
@app.route('/js/<path:path>')
def send_js(path):
return send_from_directory('js', path)
if __name__ == "__main__":
app.run()
2、可以使用app.send_file或app.send_static_file，但强烈建议不要这样做。
因为它可能会导致用户提供的路径存在安全风险。
send_from_directory旨在控制这些风险。
最后，首选方法是使用NGINX或其他Web服务器来提供静态文件，将能够比Flask更有效地做到这一点。
知识点补充：
如何在Flask中提供静态文件
import os.path
from flask import Flask, Response
app = Flask(__name__)
app.config.from_object(__name__)
def root_dir(): # pragma: no cover
return os.path.abspath(os.path.dirname(__file__))
def get_file(filename): # pragma: no cover
try:
src = os.path.join(root_dir(), filename)
# Figure out how flask returns static files
# Tried:
# - render_template
# - send_file
# This should not be so non-obvious
return open(src).read()
except IOError as exc:
return str(exc)
@app.route('/', methods=['GET'])
def metrics(): # pragma: no cover
content = get_file('jenkins_analytics.html')
return Response(content, mimetype="text/html")
@app.route('/', defaults={'path': ''})
@app.route('/<path:path>')
def get_resource(path): # pragma: no cover
mimetypes = {
".css": "text/css",
".html": "text/html",
".js": "application/javascript",
}
complete_path = os.path.join(root_dir(), path)
ext = os.path.splitext(path)[1]
mimetype = mimetypes.get(ext, "text/html")
content = get_file(complete_path)
return Response(content, mimetype=mimetype)
if __name__ == '__main__': # pragma: no cover
app.run(port=80)