时间:2021-07-23 07:37:49 | 栏目:C代码 | 点击:次
本文实例为大家分享了C++实现走迷宫小游戏的具体代码,供大家参考,具体内容如下
源码下载:C++实现走迷宫小游戏
主程序代码:
#include<conio.h> #include<stdlib.h> #include<time.h> #include<string.h> #include<windows.h> #include<iostream> using namespace std; char pr[10]={1,' ','E','O'} ; int level,n,m,map[50][50],i,j,x,y,k,ex,ey; char c[1001]; int main(){ system("cls"); puts("if you no full screen,please press full screen"); getch(); system("cls"); puts("please choose level"); again:; cin>>level; if(level>1||level<1){ puts("haven't this level"); goto again; } puts("loading..."); sprintf(c,"%d.map",level); freopen(c,"r",stdin); cin>>n>>m; for(i=1;i<=n;i++) for(j=1;j<=m;j++) cin>>map[i][j]; fclose(stdin); for(i=1;i<=n;i++) for(j=1;j<=m;j++) if(map[i][j]==3){ x=i; y=j; } else if(map[i][j]==2){ ex=i; ey=j; } while(x!=ex&&y!=ey){ system("cls"); for(i=1;i<=n;i++,putchar('\n')) for(j=1;j<=m;j++) putchar(pr[map[i][j]]); k=getch(); if(k=='w') if(map[x-1][y]&&(x-1)){ map[x-1][y]=3; map[x][y]=1; x--; } if(k=='s') if(map[x+1][y]&&(x+1)<=n){ map[x+1][y]=3; map[x][y]=1; x++; } if(k=='a') if(map[x][y-1]&&(y-1)){ map[x][y-1]=3; map[x][y]=1; y--; } if(k=='d') if(map[x][y+1]&&(y+1)<=m){ map[x][y+1]=3; map[x][y]=1; y++; } } system("cls"); return 0; }
更多C++精彩小游戏请点击专题:经典游戏 进行学习