当前位置:主页 > 脚本语言 > Shell >

Linux shell脚本实现CPU预警

时间:2021-06-29 08:28:45 | 栏目:Shell | 点击:

如果CPU占用率持续达到80以上则调用打印java线程占用率堆栈的脚本,见https://github.com/oldratlee/useful-shells/blob/master/show-busy-java-threads.sh,具体用法见他的github wiki!

#!/bin/bash
#cpu idle percent
cpu_idle=`top -b -d 1 -n 2 | grep Cpu | awk 'NR>1{print $5}' | cut -f 1 -d "."`
 
if [ -d "/opt/scripts/log" ]
then
  cd /opt/scripts
else
  mkdir /opt/scripts/log
fi
 
count=0
condition=true
while condition
do
    if [ $cpu_idle -le 20 ]
    then
      pids=`top -b -d 1 -n 1 | grep java | awk '{if($9 > 80) print $1}'`
      for ((a = 1; a < 10; a++))
      do
       for pid in $pids
       doi
         #involve jdk existence check later
         date=`date +%Y%m%d%H%M`
         sh showstack.sh -c 30 -p $pid > log/stack_$pid_$date.log
         jstat -gcutil $pid > log/gc_$pid_$date.log
       done
      done
      for pid in $pids
      do
       date=`date +%Y%m%d%H%M`
       jmap -heap $pid > log/heap_$pid_$date.log
      done
      count++
      cpu_idle=`top -b -d 1 -n 2 | grep Cpu | awk 'NR>1{print $5}' | cut -f 1 -d "."`
      if [ $count -ge 3]
      then
       #send emaili
       #server ip address
       ip=`ifconfig eth0 | grep "inet addr" | cut -f 2 -d ":" | cut -f 1 -d " "`
       condition=false
       count=0
      fi
    else
      condition=false
      count=0
    fi
done

以上所述就是本文给大家分享的全部内容了,希望大家能够喜欢。

您可能感兴趣的文章:

相关文章