时间:2020-10-16 21:56:24 | 栏目:Python代码 | 点击:次
遍历指定文件夹下的文件,根据文件后缀名,获取指定类型的文件列表;根据文件列表里的文件路径,逐个获取文件属性里的“修改时间”,如果“修改时间”与“系统当前时间”差值大于某个值,则删除该文件。
#!/usr/bin/env python # -*- coding: utf-8 -*- """Document: Remove Synctoycmd sync expired .tmp files""" import os import time import datetime def diff(): '''time diff''' starttime = datetime.datetime.now() time.sleep(10) endtime = datetime.datetime.now() print "time diff: %d" % ((endtime-starttime).seconds) def fileremove(filename, timedifference): '''remove file''' date = datetime.datetime.fromtimestamp(os.path.getmtime(filename)) print date now = datetime.datetime.now() print now print 'seconds difference: %d' % ((now - date).seconds) if (now - date).seconds > timedifference: if os.path.exists(filename): os.remove(filename) print 'remove file: %s' % filename else: print 'no such file: %s' % filename FILE_DIR = 'D:/' if __name__ == '__main__': print 'Script is running...' #diff() while True: ITEMS = os.listdir(FILE_DIR) NEWLIST = [] for names in ITEMS: if names.endswith(".txt"): NEWLIST.append(FILE_DIR + names) #print NEWLIST for names in NEWLIST: print 'current file: %s' % (names) fileremove(names, 10) time.sleep(10) print "never arrive..."