时间:2021-05-14 10:40:20 | 栏目:C代码 | 点击:次
快排的递归
void quickSort1(int* root,int low,int high) { int pat=root[low]; if(low<high) { int i=low,j=high; while(i<j) { while(i<j&&root[j]>pat) j--; root[i]=root[j]; while(i<j&&root[i]<pat) i++; root[j]=root[i]; } root[i]=pat; quickSort1(root,low,i-1); quickSort1(root,i+1,high); } }
快排的非递归
int partion(int* root,int low,int high) { int part=root[low]; while(low<high) { while(low<high&&root[high]>part) high--; root[low]=root[high]; while(low<high&&root[low]<part) low++; root[high]=root[low]; } root[low]=part; return low; } void quickSort2(int* root,int low,int high) { stack<int> st; int k; if(low<high) { st.push(low); st.push(high); while(!st.empty()) { int j=st.top();st.pop(); int i=st.top();st.pop(); k=partion(root,i,j); if(i<k-1) { st.push(i); st.push(k-1); } if(k+1<j) { st.push(k+1); st.push(j); } } } } int main() { int a[8]={4,2,6,7,9,5,1,3}; quickSort1(a,0,7); //quickSort2(a,0,7); int i; for(i=0;i<8;i++) cout<<a[i]<<" "; cout<<endl; getchar(); return 0; }
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