时间:2021-04-28 08:08:04 | 栏目:C代码 | 点击:次
rapidjson解析json代码实例
直接看代码:
#include <iostream> #include <stdio.h> #include<unistd.h> #include <sys/types.h> #include <sys/stat.h> #include <fcntl.h> #include<sstream> // 请自己下载开源的rapidjson #include "rapidjson/prettywriter.h" #include "rapidjson/rapidjson.h" #include "rapidjson/document.h" #include "rapidjson/stringbuffer.h" #include "rapidjson/writer.h" #include "rapidjson/memorystream.h" using namespace std; using rapidjson::Document; using rapidjson::StringBuffer; using rapidjson::Writer; using namespace rapidjson; string getStringFromJson(const string &jsStr, const string &strKey) { Document document; if (document.Parse(jsStr.c_str()).HasParseError() || !document.HasMember(strKey.c_str())) { return ""; } const rapidjson::Value &jv = document[strKey.c_str()]; return jv.GetString(); } int main(int argc, char *argv[]) { string s = "{\"code\":0,\"msg\":\"ok\"}"; cout << s << endl; cout << getStringFromJson(s, "msg") << endl; return 0; }
结果:
{"code":0,"msg":"ok"}
ok
注意:
1. 如果不进行document.Parse(jsStr.c_str()).HasParseError()
判断,则很容易core dump
2. 如果不进行!document.HasMember(strKey.c_str())
判断,则很容易core dump
3. code的是为0,是整数,如果调用上述getStringFromJson,会core dump,此时应该用return jv.GetInt();
OK,不多说,人生苦短,我爱rapidjson
总结