python实现列表中最大最小值输出的示例
时间:2020-10-02 10:19:55|栏目:Python代码|点击: 次
如下所示:
def findMinAndMax(L): maxL = None minL = None if L: maxL = L[0] minL = L[0] for i in range(len(L)): if L[i] > maxL: maxL = L[i] elif L[i] < minL: minL = L[i] else: maxL = None minL = None return (minL, maxL)
测试:
# 测试 if findMinAndMax([]) != (None, None): print('测试失败!') elif findMinAndMax([7]) != (7, 7): print('测试失败!') elif findMinAndMax([7, 1]) != (1, 7): print('测试失败!') elif findMinAndMax([7, 1, 3, 9, 5]) != (1, 9): print('测试失败!') else: print('测试成功!')