Mysql排序获取排名的实例代码
时间:2021-01-26 15:22:59|栏目:Mysql|点击: 次
代码如下所示:
SELECT @i:=@i+1 rowNum, if(@total=t.s_score,@rank,@rank:=@i) rank,@total:=t.s_score, t.* from( select t1.* ,t2.s_score from student t1 LEFT JOIN score t2 on t1.s_id=t2.s_id and t2.c_id="01" ORDER BY t2.s_score desc )t,(select @i:=0,@rank:=0,@total:=null) s ; SELECT @i:=@i+1 rowNum, if(@total=t.s_score,@rank,@rank:=@rank+1) rank,@total:=t.s_score, t.* from( select t1.* ,t2.s_score from student t1 LEFT JOIN score t2 on t1.s_id=t2.s_id and t2.c_id="01" ORDER BY t2.s_score desc )t,(select @i:=0,@rank:=0,@total:=null) s ;
Mysql 获取成绩排序后的名次
其实就是输出mysql的排序后的行号
RT:获取单个用户的成绩在所有用户成绩中的排名
可以分两步:
1、查出所有用户和他们的成绩排名
select id,maxScore,(@rowNum:=@rowNum+1) as rowNo from t_user, (select (@rowNum :=0) ) b order by t_user.maxScore desc
2、查出某个用户在所有用户成绩中的排名
select u.rowNo from ( select id,(@rowNum:=@rowNum+1) as rowNo from t_user, (select (@rowNum :=0) ) b order by t_user.maxScore desc ) u where u.id="2015091810371700001";
总结
上一篇:小白安装登录mysql-8.0.19-winx64的教程图解(新手必看)
栏 目:Mysql
本文标题:Mysql排序获取排名的实例代码
本文地址:http://www.codeinn.net/misctech/51409.html