linux仿写chmod命令
时间:2021-01-14 11:13:34|栏目:Shell|点击: 次
复制代码 代码如下:
#include<stdio.h>
#include<stdlib.h>
#include<sys/types.h>
#include<sys/stat.h>
int main(int argc,char **argv)
{
int mode;
int mode_u;
int mode_g;
int mode_o;
char *path;
if(argc<3)
{
printf("%s <mode num> <target file>\n",argv[0]);;
exit(0);
}
mode = atoi(argv[1]);
if(mode>777||mode<0)
{
printf("mode num error");
exit(0);
}
mode_u = mode/100;
mode_g = (mode- mode_u*100)/10;
mode_o = mode -mode_u*100-mode_g*10;
mode = mode_u*8*8+mode_g*8+mode_o;
path = argv[2];
if(chmod(path,mode)==-1)
{
perror("chmod error");
exit(1);
}
return 0;
}
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