C++中可正确获取UTF-8字符长度的函数分享
时间：2021-01-05 13:54:02|栏目：C代码|点击： 次
在C++的char*以及string中，使用的是字节流编码，即sizeof(char) == 1。
也就是说，C++是不区分字符的编码的。
而一个合法UTF8的字符长度可能为1～4位。
现在假设一串输入为UTF8编码，如何能准确的定位到每个UTF8字符的“CharPoint”，而不会错误的分割字符呢？
参考这个页面：http://www.nubaria.com/en/blog/?p=289
可以改造出下面的函数：
const unsigned char kFirstBitMask = 128; // 1000000
const unsigned char kSecondBitMask = 64; // 0100000
const unsigned char kThirdBitMask = 32; // 0010000
const unsigned char kFourthBitMask = 16; // 0001000
const unsigned char kFifthBitMask = 8; // 0000100
int utf8_char_len(char firstByte)
{
std::string::difference_type offset = 1;
if(firstByte & kFirstBitMask) // This means the first byte has a value greater than 127, and so is beyond the ASCII range.
{
if(firstByte & kThirdBitMask) // This means that the first byte has a value greater than 224, and so it must be at least a three-octet code point.
{
if(firstByte & kFourthBitMask) // This means that the first byte has a value greater than 240, and so it must be a four-octet code point.
offset = 4;
else
offset = 3;
}
else
{
offset = 2;
}
}
return offset;
}
