欢迎来到代码驿站!

Python代码

当前位置:首页 > 软件编程 > Python代码

python自动zip压缩目录的方法

时间:2022-11-01 09:19:31|栏目:Python代码|点击:

本文实例讲述了python自动zip压缩目录的方法。分享给大家供大家参考。具体实现方法如下:

这段代码来压缩数据库备份文件,没有使用python内置的zip模块,而是使用了zip.exe文件

# Hello, this script is written in Python - http://www.python.org
#
# autozip.py 1.0p
#
# This script will scan a directory (and its subdirectories)
# and automatically zip files (according to their extensions).
#
# This script does not use Python internal ZIP routines.
# InfoZip's ZIP.EXE must be present in the path (InfoZip Dos version 2.3).
# (zip23x.zip at http://www.info-zip.org/pub/infozip/)
#
# Each file will be zipped under the same name (with the .zip extension)
# eg. toto.bak will be zipped to toto.zip
#
# This script is public domain. Feel free to reuse it.
# The author is:
#    Sebastien SAUVAGE
#    <sebsauvage at sebsauvage dot net>
#    http://sebsauvage.net
#
# More quick & dirty scripts are available at http://sebsauvage.net/python/
#
# Directory to scan is hardcoded at the end of the script.
# Extensions to ZIP are hardcoded below:
ext_list = ['.bak','.trn']
import os.path, string
def autozip( directory ):
  os.path.walk(directory,walk_callback,'')
def walk_callback(args,directory,files):
  print 'Scanning',directory
  for fileName in files:
    if os.path.isfile(os.path.join(directory,fileName)) and string.lower(os.path.splitext(fileName)[1]) in ext_list:
      zipMyFile ( os.path.join(directory,fileName) )
def zipMyFile ( fileName ):
  os.chdir( os.path.dirname(fileName) )
  zipFilename = os.path.splitext(os.path.basename(fileName))[0]+".zip"
  print ' Zipping to '+ zipFilename
  os.system('zip -mj9 "'+zipFilename+'" "'+fileName+'"')
autozip( r'C:\mydirectory' )
print "All done."

希望本文所述对大家的Python程序设计有所帮助。

上一篇:基于python的itchat库实现微信聊天机器人(推荐)

栏    目:Python代码

下一篇:基于Python编写微信清理工具的示例代码

本文标题:python自动zip压缩目录的方法

本文地址:http://www.codeinn.net/misctech/217871.html

推荐教程

广告投放 | 联系我们 | 版权申明

重要申明:本站所有的文章、图片、评论等,均由网友发表或上传并维护或收集自网络,属个人行为,与本站立场无关。

如果侵犯了您的权利,请与我们联系,我们将在24小时内进行处理、任何非本站因素导致的法律后果,本站均不负任何责任。

联系QQ:914707363 | 邮箱:codeinn#126.com(#换成@)

Copyright © 2020 代码驿站 版权所有