10分钟用Python快速搭建全文搜索引擎详解流程
时间:2022-08-11 11:28:47|栏目:Python代码|点击: 次
有一个群友在群里问个如何快速搭建一个搜索引擎,在搜索之后我看到了这个
代码所在
官方很贴心,很方便的是已经提供了docker 镜像,基本pull下来就可以很方便的使用了,执行命令
cid=$(sudo docker ps -a | grep searx | awk '{print $1}') echo searx cid is $cid if [ "$cid" != "" ];then sudo docker stop $cid sudo docker rm $cid fi sudo docker run -d --name searx -e IMAGE_PROXY=True -e BASE_URL=http://yourdomain.com -p 7777:8888 wonderfall/searx
然后就可以使用了,正常查看docker的状态,就可以正常的使用了
思考
怎么样,是不是很方便,我们先看看源码是怎么样实现的
我们打开里面的代码,其实本质就是将request之后的结果做一个大的聚合,至于数据来源,我们可以是来于DB,或者文件,我们可以看一下他的核心代码
from urllib import urlencode from json import loads from collections import Iterable search_url = None url_query = None content_query = None title_query = None suggestion_query = '' results_query = '' # parameters for engines with paging support # # number of results on each page # (only needed if the site requires not a page number, but an offset) page_size = 1 # number of the first page (usually 0 or 1) first_page_num = 1 def iterate(iterable): if type(iterable) == dict: it = iterable.iteritems() else: it = enumerate(iterable) for index, value in it: yield str(index), value def is_iterable(obj): if type(obj) == str: return False if type(obj) == unicode: return False return isinstance(obj, Iterable) def parse(query): q = [] for part in query.split('/'): if part == '': continue else: q.append(part) return q def do_query(data, q): ret = [] if not q: return ret qqkey = q[0] for key, value in iterate(data): if len(q) == 1: if key == qkey: ret.append(value) elif is_iterable(value): ret.extend(do_query(value, q)) else: if not is_iterable(value): continue if key == qkey: ret.extend(do_query(value, q[1:])) else: ret.extend(do_query(value, q)) return ret def query(data, query_string): q = parse(query_string) return do_query(data, q) def request(query, params): query = urlencode({'q': query})[2:] fp = {'query': query} if paging and search_url.find('{pageno}') >= 0: fp['pageno'] = (params['pageno'] - 1) * page_size + first_page_num params['url'] = search_url.format(**fp) params['query'] = query return params def response(resp): results = [] json = loads(resp.text) if results_query: for result in query(json, results_query)[0]: url = query(result, url_query)[0] title = query(result, title_query)[0] content = query(result, content_query)[0] results.append({'url': url, 'title': title, 'content': content}) else: for url, title, content in zip( query(json, url_query), query(json, title_query), query(json, content_query) ): results.append({'url': url, 'title': title, 'content': content}) if not suggestion_query: return results for suggestion in query(json, suggestion_query): results.append({'suggestion': suggestion}) return results
结果
每个response的时候我们都要以轻松的定制返回的数据(可以是网络,可以是数据库,可以是文件),那我们进一步想一下,如果我们可以hack response 结果,那我们完全可以将自己爬来的数据做为返回结果。如果是1024之类的,完全可以打造自己的“爱好”小引擎,代码我就不贴了,大家可以自己动手自己玩玩。结合jieba分词,可以更好玩一点。