C语言代码实现井字棋游戏
时间:2022-06-23 11:40:09|栏目:C代码|点击: 次
井字棋是一个很常见的小游戏。要求对战双方在一个“井”形的棋盘里分别下“*”棋子或者“#”棋子,谁先连成3个,谁就赢。
本次使用C语言来实现这个小游戏。
由于使用函数较多,所以采用多文件的方式方便梳理代码思路。
本次一共有三个文件:
**
game.h:
包含了game.c文件中函数的声明和库函数的声明。**
#pragma once #define ROW 3 #define COL 3 #include<stdio.h> #include<stdlib.h> #include<time.h> void InitBoard(char board [ROW][COL], int row, int col); //初始化棋盘 void DisplayBoard(char board [ROW][COL], int row, int col); //打印棋盘 void PlayerBoard(char board [ROW][COL], int row, int col); //玩家走 void ComputerBoard(char board [ROW][COL], int row, int col);//电脑走 char IsWin(char board [ROW][COL], int row, int col); //结果判断
game.c:
包含游戏过程中关键函数的函数主体。
#define _CRT_SECURE_NO_WARNINGS #include"game.h" void InitBoard(char board[ROW][COL], int row, int col) { //初始化棋盘 int i = 0; for (i = 0; i < row; i++) { int j = 0; for (j = 0; j < col; j++) board [i][j] = ' '; } } void DisplayBoard(char board [ROW][COL], int row, int col) { //打印棋盘 int i = 0; for (i = 0; i < row; i++) { int j = 0; for (j = 0; j < col; j++) { printf(" %c ", board [i][j]); if (j < col - 1) printf("|"); } printf("\n"); if (i < row - 1) { for (j = 0; j < col; j++) { printf("---"); if (j < col - 1) printf("|"); } printf("\n"); } } } void PlayerBoard(char board [ROW][COL], int row, int col) { int x = 0, y = 0; while (1) { printf("输入棋子坐标->"); scanf("%d%d", &x, &y); if (x > 0 && x <= row && y > 0 && y <= col) { if (board [x - 1][y - 1] == ' ') { board [x - 1][y - 1] = '*'; break; } else { printf("此位置已有棋子!请重新输入。\n"); } } else { printf("输入错误!请重新输入。\n"); } } } void ComputerBoard(char board [ROW][COL], int row, int col) { int x = 0, y = 0; while (1) { x = rand() % row; y = rand() % col; if (board [x][y] != ' ') { continue; } else { board [x][y] = '#'; break; } } } int IsFull(char board [ROW][COL], int row, int col) { int i = 0; for (i = 0; i < row; i++) { int j = 0; for (j = 0; j < col; j++) { if (board [i][j] == ' ') return 0; } } return 1; } char IsWin(char board [ROW][COL], int row, int col) { int i = 0; //行 for (i = 0; i < row; i++) { if (board [i][0] == board [i][1] && board [i][1] == board [i][2] && board [i][0] != ' ') return board [i][0]; } //列 for (i = 0; i < col; i++) { if (board [0][i] == board [1][i] && board [1][i] == board [2][i] && board [0][i] != ' ') return board [0][i]; } //对角线 if (board [0][0] == board [1][1] && board [1][1] == board [2][2] & board [1][1] != ' ') return board [1][1]; if (board [2][0] == board [1][1] && board [1][1] == board [0][2] & board [1][1] != ' ') return board [1][1]; //是否平局 if (IsFull(board, row, col)) return 'Q';//平局 return 'C';//继续 }
test.c:
main函数和游戏的大概流程。
#define _CRT_SECURE_NO_WARNINGS #include"game.h" void Menu() { printf("*******************************\n"); printf("********** 1、play **********\n"); printf("********** 0、quit **********\n"); printf("*******************************\n"); } void game() { char board [ROW][COL]; InitBoard(board, ROW, COL); DisplayBoard(board, ROW, COL); char ret = 0; srand((unsigned int) time(NULL)); while (1) { printf("玩家走\n"); PlayerBoard(board, ROW, COL); DisplayBoard(board, ROW, COL); ret = IsWin(board, ROW, COL); if (ret != 'C') break; printf("电脑走\n"); ComputerBoard(board, ROW, COL); DisplayBoard(board, ROW, COL); ret = IsWin(board, ROW, COL); if (ret != 'C') break; } if (ret == '*') printf("玩家胜利!\n"); else if (ret == '#') printf("电脑胜利!\n"); else printf("平局!\n"); } int main() { //三子棋 int input = 1; while (input) { Menu(); printf("输入1开始游戏,输入0退出游戏。\n请输入->"); scanf("%d", &input); switch(input) { case 1: game(); printf("开始游戏\n"); break; case 0: printf("游戏结束\n"); break; default: printf("非法输入,请重试!\n"); } } return 0; }
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