用C语言实现简单扫雷小游戏

#pragma once
#define ROW 9
#define COL 9
#define ROWS ROW+2
#define COLS COL+2
#define EASY_COUNT 10
#include<stdlib.h>
#include<time.h>
//初始化棋盘
void initboard(char board[ROWS][COLS], int rows, int cols,char s);

//打印棋盘
void displayboard(char board[ROWS][COLS], int row, int col);

//布置雷
void setmine(char board[ROWS][COLS], int row, int col);

//排查雷
void findmine(char board[ROWS][COLS], char show[ROWS][COLS], int row, int col);

#define _CRT_SECURE_NO_WARNINGS
#include"game.h"
#include<stdio.h>
void initboard(char board[ROWS][COLS], int rows, int cols,char s)
{
 int i = 0;
 for (i = 0;i < rows;i++)
 {
  int j = 0;
  for (j = 0;j < cols;j++)
  {
   board[i][j] = s;
  }
 }
}

void displayboard(char board[ROWS][COLS], int row, int col)
{
 int i = 0;
 printf("--------------------------------\n");
 for (i = 0;i <= 9;i++)
 {
  printf("%d ", i);
 }
 printf("\n");
 for (i = 1;i <= row;i++)
 {
  int j = 0;
  printf("%d ", i);
  for (j = 1;j <= col;j++)
  {
   printf("%c ", board[i][j]);
  }
  printf("\n");
 }
 printf("--------------------------------\n");
}
 

void setmine(char board[ROWS][COLS], int row, int col)
{
 int count = EASY_COUNT;
 while (count)
 {
  //1.生成随机下标（1-9）
  int x = rand() % row + 1;
  int y = rand() % col + 1;
  if (board[x][y] != '1')//布置雷要考虑某块地方是否已经被安放过雷
  {
   board[x][y] = '1';
   count--;//判断雷布置成功（没有覆盖其他雷），雷个数才减少
  }
 }
}

int getminecount(char mine[ROWS][COLS],int x,int y)
{
 return mine[x - 1][y] + mine[x - 1][y - 1] + mine[x - 1][y + 1] + mine[x][y - 1] + mine[x][y + 1] + mine[x + 1][y - 1] + mine[x + 1][y] + mine[x + 1][y + 1] - 8 * '0';//符号数字-‘0'=数字（十进制），详情见ascll码表
}

void findmine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col)
{
 int x = 0;
 int y = 0;
 int win = 0;
 while (win<row*col-EASY_COUNT)
 {
  printf("请输入要排查的坐标：>");
  scanf("%d %d", &x, &y);
  if (x >= 1 && x <= row && y >= 1 && y <= col)
  {
   if (mine[x][y] == '1')
   {
    printf("你踩到了雷！\n");
    displayboard(mine, ROW, COL);
    break;
   }
   else
   {
    int count = getminecount(mine, x, y);
    show[x][y] = count + '0';
    displayboard(show, ROW, COL);
    win++;
   }
  }
  else
  {
   printf("坐标输入错误，请重新输入：\n");
  }
 }
 if (win == row * col - EASY_COUNT)
 {
  printf("You win!\n");
  displayboard(show, ROW, COL);
 }
}

#define _CRT_SECURE_NO_WARNINGS
#include<stdio.h>
#include"game.h"
void menu()
{
 printf("************************\n");
 printf("******** 1.play ********\n");
 printf("******** 0.exit ********\n");
 printf("************************\n");
}
void game()
{
 char mine[ROWS][COLS] = {0};//存放雷的信息
 char show[ROWS][COLS] = {0};//存放排查出雷的信息
 //初始化棋盘
 initboard(mine, ROWS, COLS,'0');//用‘0'覆盖
 initboard(show, ROWS, COLS,'*');//用‘*'覆盖
 /*displayboard(mine,ROW,COL);
 displayboard(show, ROW, COL);*/
 //布置雷
 setmine(mine, ROW, COL);
 displayboard(show, ROW, COL);
 //displayboard(mine, ROW, COL);//对检查能否通关时，进行一次排查要完成一次扫雷游戏，时间太长，也不方便，可以将9*9的棋盘雷设置为80个，打印出雷所在位置,再进行排查1次即可
 //排查雷
 findmine(mine,show,ROW,COL);

}
int main()
{
 int input = 0;
 srand((unsigned int)time(NULL));
 do
 {
  menu();
  printf("请输入1进行游戏 或0退出游戏\n");
  scanf("%d", &input);
  switch (input)
  {
  case 1:
   game();
   break;
  case 0:
   printf("退出游戏\n");
   break;
  default:
   printf("选择错误\n");
   break;
  }
 } while (input);
}