字符串中找出连续最长的数字字符串的实例代码
时间:2021-09-27 09:43:25|栏目:C代码|点击: 次
复制代码 代码如下:
//1. 写一个函数,它的原形是int continumax(char *outputstr,char *intputstr)
//功能:
//在字符串中找出连续最长的数字串,并把这个串的长度返回,
//并把这个最长数字串付给其中一个函数参数outputstr所指内存。
//例如:"abcd12345ed125ss123456789"的首地址传给intputstr后,函数将返回9,outputstr所指的值为123456789
#include<stdio.h>
#include<assert.h>
int continumax(char *outputstr,char *inputstr)
{
assert(outputstr);
assert(inputstr);
int length = 0;
int maxlength = 0;
int i = 0;
int j = 0;
while(inputstr[i] != '\0')
{
while( inputstr[i] >='0'&& inputstr[i] <= '9')
{
length++;
i++;
}
if(length > maxlength)
{
maxlength = length;
int k = i-maxlength;
for(j = 0; j < maxlength; j++ )
{
outputstr[j] =inputstr[k++];
}
length = 0;
continue;
}
i++;
length = 0;
}
outputstr[j] = '\0';
return maxlength;
}
int main( )
{
char inputstr[ ]= "abcd12345eddafsd125ss123456789";
char outputstr[100];
int max_numstr_length = continumax(outputstr,inputstr);
printf("%s\n",outputstr);
printf("the max_numstr_length is %d\n", max_numstr_length);
return 0;
}
复制代码 代码如下:
#include<iostream.h>
#include<malloc.h>
int continumax(char * outputstr, char * inputstr)
{
int len = 0; //统计数字字符串的长度
int max = 0; //当前最大数字字符串的长度
char *pstr =NULL; //记录最大数字字符的起始位置
while(* inputstr!= '\0')
{
if(*inputstr <= '9' && *inputstr >='0') //统计数字子字符串的长度
{
len++;
inputstr++;
continue;
}
else if (len > max) //如果统计出来的数字字符串大于当前的最大数字子字符串的长度,则更新
{
max = len;
pstr = inputstr-len;
len = 0;
}
inputstr++;
}
for(int i = 0 ; i<max;i++) //将最大子字符串的值拷贝给outputstr
{
*outputstr = *pstr;
outputstr++;
pstr++;
}
outputstr = outputstr-max;
outputstr[max] ='\0';
cout<<outputstr<<endl;
return max;
}
int main()
{
char input[] = "de1234de123456ed";
//char * out = (char *)malloc(100*sizeof(char));
char output[100];
int max = continumax(output, input);
cout<<max<<endl;
return 0;
}