如何通过SQL找出2个表里值不同的列的方法
时间：2021-09-03 09:19:30|栏目：Mysql|点击： 次
以下有两个表，他们的结构完全相同，请通过SQL找出值不同的列。
Student_1
| NAME | AGE | SCORE |
| peter | 26 | 100 |
| jack | 25 | 96 |
| daniel | 26 | 48 |
| bark | 21 | 69 |
Student_2
| NAME | AGE | SCORE |
| peter | 26 | 89 |
| jack | 25 | 96 |
| daniel | 26 | 48 |
| bark | 21 | 69 |
方法一 -- NOT EXISTS：
复制代码 代码如下:
SELECT *
FROM Student_1 S1
WHERE NOT EXISTS
(SELECT *
FROM Student_2 S2
WHERE S1.name = S2.name
AND S1.age = S2.age
AND S1.score = S2.score
)
UNION ALL
SELECT *
FROM STUDENT_2 S2
WHERE NOT EXISTS
(SELECT *
FROM STUDENT_1 S1
WHERE S1.name = S2.name
AND S1.age = S2.age
AND S1.score = S2.score
);
方法二 -- MINUS
复制代码 代码如下:
(SELECT * FROM Student_1
MINUS
SELECT * FROM Student_2)
UNION ALL
(SELECT * FROM Student_2
MINUS
SELECT * FROM Student_1)
方法三 -- HAVING GROUP BY
复制代码 代码如下:
SELECT DISTINCT name, age, score FROM (
SELECT * FROM Student_1
UNION ALL
SELECT * FROM Student_2
)GROUP BY name, age, score HAVING COUNT(*)=1 ;
