C++基于EasyX实现简单扫雷游戏
时间:2021-08-16 09:21:39|栏目:C代码|点击: 次
本文实例为大家分享了C++ EasyX实现简单扫雷游戏的具体代码,供大家参考,具体内容如下
【实现代码】
#include <cmath> #include <time.h> #include <easyx.h> #include <conio.h> using namespace std; #define Size 500 //定义窗口大小 #define SquareSize 50 //定义格子大小 #define BackGroundColor LIGHTGRAY //定义背景颜色 const int N = Size / SquareSize; //设置地图大小为N * N const int Num = N * N / 5; //设置总地雷数 int num = Num, all = N * N - Num; //剩余地雷数和未格子访问数 int Map[N + 10][N + 10]; //地图表示(i, j)旁边的地雷数目,等于-1表示该位置为地雷 bool vis[N + 10][N + 10]; //标记是否(i, j)被访问 bool vis_lm[N + 10][N + 10]; //标记(i, j)是否被标记为地雷 int dx[] = { 0, 0, 1, -1, 1, -1, 1, -1 }; int dy[] = { 1, -1, 0, 0, 1, -1, -1, 1 }; void Init() { initgraph(Size, Size); setbkcolor(BackGroundColor); settextcolor(YELLOW); settextstyle(25, 0, _T("宋体")); cleardevice(); } void BuildGameMap() { //构建地图 srand((unsigned int)time(NULL)); //产生随机数 for (int i = 1; i <= Num; ++i) { int x = rand() % N + 1, y = rand() % N + 1; while (Map[x][y] == -1) { x = rand() % N + 1, y = rand() % N + 1; } Map[x][y] = -1; } //计算每个格子旁边的地雷数目 for (int i = 1; i <= N; ++i) { for (int j = 1; j <= N; ++j) { if (Map[i][j] == -1) continue; for (int k = 0; k < 8; ++k) { if (Map[i + dx[k]][j + dy[k]] == -1) ++Map[i][j]; } } } } void InitGameGraph() { //地图初始化 memset(Map, 0, sizeof(Map)); memset(vis, false, sizeof(vis)); memset(vis_lm, false, sizeof(vis_lm)); num = Num, all = N * N - Num; BuildGameMap(); cleardevice(); //清屏 setfillcolor(WHITE); for (int i = 0; i <= Size; i += SquareSize) { line(i, 0, i, Size); } for (int i = 0; i <= Size; i += SquareSize) { line(0, i, Size, i); } } int Translate_X(int x) { //左边变换 return x * SquareSize + SquareSize / 2; } void GameOver(bool tag) { RECT r = { 0, 0, Size - 1, Size - 1 }; if (tag) { drawtext(_T("Win"), &r, DT_CENTER | DT_VCENTER | DT_SINGLELINE); } else { //游戏失败画出所有地雷 setfillcolor(RED); for (int i = 1; i <= N; ++i) { for (int j = 1; j <= N; ++j) { if (Map[i][j] == -1) { if (vis_lm[i][j]) continue; //该地雷已被玩家标记,跳过 outtextxy(Translate_X(i - 1), Translate_X(j - 1), 'X'); //否则显示出来 } else if (vis_lm[i][j]) { //玩家标记了错误的地雷,标红 fillcircle(Translate_X(i - 1), Translate_X(j - 1), SquareSize / 2 - 10); } } } drawtext(_T("Failed"), &r, DT_CENTER | DT_VCENTER | DT_SINGLELINE); } } void Help() { //调试函数(其实是挂) for (int i = 1; i <= N; ++i) { for (int j = 1; j <= N; ++j) { if (Map[i][j] == -1) { outtextxy(Translate_X(i - 1), Translate_X(j - 1), 'X'); } } } } void StartGame() { Init(); while (true) { InitGameGraph(); //Help(); bool IF_WIN = true; while (all || num) { //胜利条件是所有非地雷格子均被访问且所有地雷均被标记 MOUSEMSG msg = GetMouseMsg(); //获取用户鼠标信息 int x = ceil(msg.x * 1.0 / SquareSize * 1.0), y = ceil(msg.y * 1.0 / SquareSize * 1.0); if (vis[x][y]) continue; //该格已被访问,跳过 if (msg.mkLButton) { //鼠标左键按下 if (Map[x][y] == -1) { //如果是地雷那么游戏结束 IF_WIN = false; break; } outtextxy(Translate_X(x - 1), Translate_X(y - 1), Map[x][y] + '0'); --all; vis[x][y] = true; } else if (msg.mkRButton) { //鼠标右键按下 if (!vis_lm[x][y]) { //如果该格子已被标记,消除标记 vis_lm[x][y] = true; if (Map[x][y] == -1) --num; solidcircle(Translate_X(x - 1), Translate_X(y - 1), SquareSize / 2 - 10); } else if (vis_lm[x][y]) { //否则标记 vis_lm[x][y] = false; if (Map[x][y] == -1) ++num; clearrectangle((x - 1) * SquareSize + 1, (y - 1) * SquareSize + 1, x * SquareSize - 1, y * SquareSize - 1); } } } GameOver(IF_WIN); int t = _getch(); } } int main() { StartGame(); return 0; }