python查找特定名称文件并按序号、文件名分行打印输出的方法

# -*- coding: utf-8 -*-
# 查找特定名称文件
# 2020-04-22

# 导入OS模块
import os
# 待搜索的目录路径
path = "Day1-homework"
# 待搜索的名称
filename = "2020"
# 定义保存结果的数组
result = []

def findfiles():
  """查找特定名称文件"""

  # 判断路径是否存在
  if path:
    # 定义符合文件名的个数，也即循环次数
    i = 0
    # walk方法产生3-元组 (dirpath, dirnames, filenames)
    for dirpath, dirnames, filenames in os.walk(path):
      # 遍历filenames赋值file
      for file in filenames:
        if "2020" in file:
          # join方法合并出完整路径
          result = [os.path.join(dirpath,file)]
          i += 1
          j = [i]
          print(j + result)
  else:
    print ("The dirpath in not Exist!")
        


if __name__ == '__main__':
  findfiles()
[1, 'Day1-homework/4/22/04:22:2020.txt']
[2, 'Day1-homework/18/182020.doc']
[3, 'Day1-homework/26/26/new2020.txt']

import os
  path = os.getcwd()
  files = os.listdir(path)
  for file in files:
    if file == 'Please_Find_Me' :
      print(file)
      break