layui结合form,table的全选、反选v1.0示例讲解

<div class="layui-form">
<table class="layui-table">
  <thead>
    <tr>
      <td>
        <input type="checkbox" name="" lay-skin="primary" lay-filter="allChoose">
      </td>
      <td>ID</td>
      <td>角色名</td>
      <td>唯一标识</td>
      <td>状态</td>
      <td>操作</td>
    </tr>
  </thead>
  <tbody class="role_list">
    <tr>
      <td>
        <input type="checkbox" name="" lay-skin="primary" lay-filter="itemChoose">
      </td>
      <td>1</td>
      <td>xxx</td>
      <td>xxx</td>
      <td>xxx</td>
      <td>xxx</td>
    </tr>
  </tbody>
</table>
</div>

form.on('checkbox(allChoose)', function(data){
  var child = $(data.elem).parents('table').find('tbody input[type="checkbox"]');
  child.each(function(index, item){
    item.checked = data.elem.checked;
  });
  form.render('checkbox');
});
form.on('checkbox(itemChoose)',function(data){
  var sib = $(data.elem).parents('table').find('tbody input[type="checkbox"]:checked').length;
  var total = $(data.elem).parents('table').find('tbody input[type="checkbox"]').length;
  if(sib == total){
    $(data.elem).parents('table').find('thead input[type="checkbox"]').prop("checked",true);
    form.render();
  }else{
    $(data.elem).parents('table').find('thead input[type="checkbox"]').prop("checked",false);
    form.render();
  }
});