详解Java无需解压直接读取Zip文件和文件内容
时间:2020-10-09 13:09:45|栏目:JAVA代码|点击: 次
整理文档,搜刮出一个Java无需解压直接读取Zip文件和文件内容的代码,稍微整理精简一下做下分享。
package test; import java.io.BufferedInputStream; import java.io.BufferedReader; import java.io.FileInputStream; import java.io.InputStream; import java.io.InputStreamReader; import java.util.zip.ZipEntry; import java.util.zip.ZipFile; import java.util.zip.ZipInputStream; public class aaaa { public static void main(String[] args) throws Exception { try { readZipFile("D:\\ztree.zip"); } catch (Exception e) { // TODO Auto-generated catch block e.printStackTrace(); } } public static void readZipFile(String file) throws Exception { ZipFile zf = new ZipFile(file); InputStream in = new BufferedInputStream(new FileInputStream(file)); ZipInputStream zin = new ZipInputStream(in); ZipEntry ze; while ((ze = zin.getNextEntry()) != null) { if (ze.isDirectory()) { } else { System.err.println("file - " + ze.getName() + " : " + ze.getSize() + " bytes"); long size = ze.getSize(); if (size > 0) { BufferedReader br = new BufferedReader( new InputStreamReader(zf.getInputStream(ze))); String line; while ((line = br.readLine()) != null) { System.out.println(line); } br.close(); } System.out.println(); } } zin.closeEntry(); } }
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