详谈ajax返回数据成功 却进入error的方法

PrintWriter out = response.getWriter(); 
response.setHeader(“Access-Control-Allow-Origin”, “*”); 
response.setHeader(“Access-Control-Allow-Methods”, “POST, GET, OPTIONS, DELETE”); 
response.setHeader(“Access-Control-Max-Age”, “3600”); 

function submits(){
  $.ajax({
     type:"post",
     url:"http://localhost:8082/TFS.WEB/servlet/Servlet",
     data: $("#form1").serialize(),
     success: function (data) {
         data = JSON.stringify(data);
         alert(data); 
          },
     error:function(jqXHR,textStatus,errorThrown){ 
        alert("！！！!"); 
        console.log(jqXHR); 
        console.log(textStatus); 
        console.log(errorThrown); 
          } 
    }); 

}


</script>