PHP实现数组根据某个字段进行水平合并，横向合并案例分析
时间：2020-10-14 10:05:27|栏目：PHP代码|点击： 次
本文实例讲述了PHP实现数组根据某个字段进行水平合并，横向合并。分享给大家供大家参考，具体如下：
PHP数组水平合并，横向合并，两条数据合并成一行
需求
将两个素组中日期相同的合并成一行
数组a
Array
(
[0] => Array
(
[date] => 2019-04-02
[today_pay_money] => 168.00
[today_pay_num] => 1
[yesterday_pay_money] => 999.00
[yesterday_pay_num] => 1
)
[1] => Array
(
[date] => 2019-04-09
[today_pay_money] => 0.01
[today_pay_num] => 1
[yesterday_pay_money] => 0.00
[yesterday_pay_num] => 0
)
[2] => Array
(
[date] => 2019-05-05
[today_pay_money] => 0.01
[today_pay_num] => 1
[yesterday_pay_money] => 2.00
[yesterday_pay_num] => 1
)
[3] => Array
(
[date] => 2019-05-11
[today_pay_money] => 0.00
[today_pay_num] => 0
[yesterday_pay_money] =>
[yesterday_pay_num] => 1
)
)
数组B
Array
(
[0] => Array
(
[date] => 2019-05-07
[today_pay_money1] => 0
[today_pay_num1] => 0
[yesterday_pay_money1] => 0
[yesterday_pay_num1] => 0
)
[1] => Array
(
[date] => 2019-05-11
[today_pay_money1] => 0
[today_pay_num1] => 0
[yesterday_pay_money1] => 1
[yesterday_pay_num1] => 1
)
)
需要格式
Array
(
[2019-04-02] => Array
(
[date] => 2019-04-02
[today_pay_money] => 168.00
[today_pay_num] => 1
[yesterday_pay_money] => 999.00
[yesterday_pay_num] => 1
)
[2019-04-09] => Array
(
[date] => 2019-04-09
[today_pay_money] => 0.01
[today_pay_num] => 1
[yesterday_pay_money] => 0.00
[yesterday_pay_num] => 0
)
[2019-05-05] => Array
(
[date] => 2019-05-05
[today_pay_money] => 0.01
[today_pay_num] => 1
[yesterday_pay_money] => 2.00
[yesterday_pay_num] => 1
)
[2019-05-11] => Array
(
[date] => 2019-05-11
[today_pay_money] => 0.00
[today_pay_num] => 0
[yesterday_pay_money] =>
[yesterday_pay_num] => 1
[today_pay_money1] => 0
[today_pay_num1] => 0
[yesterday_pay_money1] => 1
[yesterday_pay_num1] => 1
)
[2019-05-07] => Array
(
[date] => 2019-05-07
[today_pay_money1] => 0
[today_pay_num1] => 0
[yesterday_pay_money1] => 0
[yesterday_pay_num1] => 0
)
)
代码实现
先将a,b数组合并，判断当前日期下是否空，空的话直接赋值，不空的话，将已有素组和当前数组合并
$total = array_merge($a,$b));
$res = array();
foreach ($total as $k => $v) {
if (empty($res[$v['date']]))
$res[$v['date']] = $v;
else
$res[$v['date']]= array_merge($res[$v['date']],$v);
}
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希望本文所述对大家PHP程序设计有所帮助。
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