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C#获取某路径文件夹中全部图片或其它指定格式的文件名的实例方法

时间:2020-12-03 17:38:26 | 栏目:.NET代码 | 点击:

1、编写获取文件名(全路径)子函数

/////param
///path:文件夹路径
///suffix:后缀格式, 如bmp,txt
///fileList:文件名存放
///isSubcatalog:true遍历子文件夹,否则不遍历
void getFiles(string path, string suffix, ref List<string> fileList, bool isSubcatalog)
{
  string filename;
  DirectoryInfo dir = new DirectoryInfo(path);
  FileInfo[] file = dir.GetFiles();
  //DirectoryInfo[] dii = dir.GetDirectories();//如需遍历子文件夹时需要使用
  foreach (FileInfo f in file)
  {
    filename = f.FullName;
    if (filename.EndsWith(suffix))//判断文件后缀,并获取指定格式的文件全路径增添至fileList
    {
      fileList.Add(filename);
    }
  }
  获取子文件夹内的文件列表,递归遍历 
  if(isSubcatalog)
  {
    foreach (DirectoryInfo d in dii)
    {
      getFiles(d.FullName, fileList);
    }
  }

  return;
}

2、在界面中放置一个button控件,单击按钮时弹出文件夹路径选择窗口,并调用getFiles子函数:

List<string> imageFiles = new List<string>();
private void btnSelectPath_Click(object sender, EventArgs e)
{
  FolderBrowserDialog dialog = new FolderBrowserDialog();
  dialog.Description = "Please choose image path.";
  DialogResult result = dialog.ShowDialog();
  if (result == System.Windows.Forms.DialogResult.Cancel)
  {
    return;
  }
  string folderPath = dialog.SelectedPath.Trim();
  DirectoryInfo theFolder = new DirectoryInfo(folderPath);
  if (theFolder.Exists)
  {
    getFiles(folderPath,"bmp", ref imageFiles, false);
    return; 
  }
}

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