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vue.js实现只弹一次弹框

时间:2020-11-25 11:44:19 | 栏目:vue | 点击:

核心代码是 getCookie()部分,控制弹框的显示隐藏则在 created()中。

<template>
 <div v-if="isShow"> <!--最外层背景-->
  <div class="popup_container"> <!--居中的容器-->
   <img @click="noPopup" src="delete.png" alt=""> <!--关闭弹框-->
   <div class="popup_text"> <!--内容部分-->
    Lorem ipsum dolor sit amet, consectetur adipisicing elit. At, atque ea eveniet laudantium magni, maiores nam nihil non numquam odio pariatur perferendis placeat quas quasi sit soluta, sunt ullam voluptatibus.  
   </div>
  </div>
 </div>
</template>
<script>
 export default {
  data(){
   return{
    isShow: true,
   }
  },
  created(){
   if (this.getCookie('popped') == ''){ //cookie 中没有 popped 则赋给他一个值(此时弹框显示)
    document.cookie = "popped = yes";
   }else{
    this.isShow = false; //若cookie 中已经有 popped 值,则弹框再不会显示
   }
  },
  methods: {
   noPopup(){
    this.isShow = false;
   },
   getCookie(Name) { //cookie
    var search = Name + "=";
    var returnValue = "";
    if (document.cookie.length > 0) {
     var offset = document.cookie.indexOf(search);
     if (offset !== -1) {
      offset += search.length;
      var end = document.cookie.indexOf(";", offset);
      if (end == -1){
       end = document.cookie.length;
      }
      returnValue = decodeURIComponent(document.cookie.substring(offset, end));
     }
    }
    return returnValue;
   },
  },
 }
</script>
<style scoped>
  /*样式部分*/
</style>

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