时间:2023-02-17 15:52:50 | 栏目:Oracle | 点击:次
create table nayi224_180824(col_1 varchar2(10), col_2 varchar2(10), col_3 varchar2(10)); insert into nayi224_180824 select 1, 2, 3 from dual union all select 1, 2, 3 from dual union all select 5, 2, 3 from dual union all select 10, 20, 30 from dual ; commit; select*from nayi224_180824;
COL_1 | COL_2 | COL_3 |
---|---|---|
1 | 2 | 3 |
1 | 2 | 3 |
5 | 2 | 3 |
10 | 20 | 30 |
select distinct t1.* from nayi224_180824 t1;
COL_1 | COL_2 | COL_3 |
---|---|---|
10 | 20 | 30 |
1 | 2 | 3 |
5 | 2 | 3 |
方法局限性很大,因为它只能对全部查询的列做去重。如果我想对col_2,col3去重,那我的结果集中就只能有col_2,col_3列,而不能有col_1列。
select distinct t1.col_2, col_3 from nayi224_180824 t1
COL_2 | COL_3 |
---|---|
2 | 3 |
20 | 30 |
不过它也是最简单易懂的写法。
select * from (select t1.*, row_number() over(partition by t1.col_2, t1.col_3 order by 1) rn from nayi224_180824 t1) t1 where t1.rn = 1 ;
COL_1 | COL_2 | COL_3 | RN |
---|---|---|---|
1 | 2 | 3 | 1 |
10 | 20 | 30 | 1 |
写法上要麻烦不少,但是有更大的灵活性。
select * from nayi224_180824 t where (t.col_2, t.col_3) in (select t1.col_2, t1.col_3 from nayi224_180824 t1 group by t1.col_2, t1.col_3 having count(1) > 1)
COL_1 | COL_2 | COL_3 |
---|---|---|
1 | 2 | 3 |
1 | 2 | 3 |
5 | 2 | 3 |
要查两次表,效率会比较低。不推荐。
select * from (select t1.*, count(1) over(partition by t1.col_2, t1.col_3) rn from nayi224_180824 t1) t1 where t1.rn > 1 ;
COL_1 | COL_2 | COL_3 | RN |
---|---|---|---|
1 | 2 | 3 | 3 |
1 | 2 | 3 | 3 |
5 | 2 | 3 | 3 |
只需要查一次表,推荐。
delete from nayi224_180824 t where t.rowid in ( select rid from (select t1.rowid rid, count(1) over(partition by t1.col_2, t1.col_3) rn from nayi224_180824 t1) t1 where t1.rn > 1);
就是上面的语句稍作修改。
delete from nayi224_180824 t where t.rowid in (select rid from (select t1.rowid rid, row_number() over(partition by t1.col_2, t1.col_3 order by 1) rn from nayi224_180824 t1) t1 where t1.rn > 1);
拥有分析函数一贯的灵活性高的特点。可以为所欲为的分组,并通过改变orderby从句来达到像”保留最大id“这样的要求。
delete from nayi224_180824 t where t.rowid not in (select max(rowid) from nayi224_180824 t1 group by t1.col_2, t1.col_3);
牺牲了一部分灵活性,换来了更高的效率。