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sqlite查询结果在listview中展示的实现

时间:2021-08-12 09:32:09 | 栏目:Android代码 | 点击:

1、获取db实例

SQLiteDatabase db=dbhelper.getWritableDatabase(); 

2、Cursord对象获取查询结构

Cursor cursor=db.rawQuery("select * from good where number>3",null); 

3、新建SimplecursorAdapter对象

SimpleCursorAdapter cursorAdapter=new SimpleCursorAdapter(this, R.layout.golist_item, cursor, new String[]{"_id","name", "price","number"},new int[]{R.id.textView2,R.id.textView3,R.id.textView4,R.id.textView1},CursorAdapter.FLAG_REGISTER_CONTENT_OBSERVER); 

simplecusoradapter的构造方法有6个参数(上下文环境,listview布局文件,游标,列名(new string[]{}),显示内容(new int[]{}),flag设置监听)

4、setadapter(cursorAdapter);

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