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在Android中访问WebService接口的方法

时间:2021-07-08 14:47:00 | 栏目:Android代码 | 点击:

需要引入ksoap2-android-assembly-2.5.2-jar-with-dependencies.jar
复制代码 代码如下:

  //WebService的命名空间
  static final String namespace = "http://impl.service.suncreate.com";
  //服务器发布的url
  static final String url = http://10.100.3.41/axis2/services/UploadService;
  final String methodName = "upload"; // 函数名
  final int sessionID = "111111";  //sessionID
  //创建HttpTransportSE对象,通过HttpTransportSE类的构造方法可以指定WebService的url
  HttpTransportSE transport = new HttpTransportSE(url);
  transport.debug = true;
  //指定WebService的命名空间和函数名
  SoapObject soapObject = new SoapObject(namespace, methodName);
  //设置调用方法参数的值
  soapObject.addProperty("sessionID", sessionID); //sessionID
  soapObject.addProperty("data", cds); //cds是需要传递的对象
  SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER10);
  envelope.bodyOut = transport;
  envelope.setOutputSoapObject(soapObject);
  //使用call方法调用WebService方法
  transport.call(null, envelope);
  SoapObject sb = (SoapObject) envelope.bodyIn;
  String xmlMessage = sb.toString(); // 获取从服务器端返回的XML字符串

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